11x^2-5x+3=x^2-4x

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Solution for 11x^2-5x+3=x^2-4x equation: 



11x^2-5x+3=x^2-4x

We move all terms to the left:

11x^2-5x+3-(x^2-4x)=0

We get rid of parentheses

11x^2-x^2-5x+4x+3=0

We add all the numbers together, and all the variables

10x^2-1x+3=0

a = 10; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·10·3
Δ = -119
Delta is less than zero, so there is no solution for the equation

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